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Monday, February 24, 2014

Monday!

Today started our first 5 day week of school in a loooooong time. Hope you're ready for it!

Tonight, please complete the "Juana and Carroll" AP problem. This deals with expected value and the stuff we learned prior--so no binomial or geometric probability on this one.

Period B (or anyone who was absent or lost the paper): You can find the questions below. Enjoy!

AP Free Response Problem:
A nearby video store is holding a tournament where contestants play a video game with scores ranging from 0 to 20. There are multiple game stations set up so that all contestants play simultaneously; thus, contestant scores are independent. Each score will be recorded as a player finishes, and the player with the highest score is the winner.
After practicing many times, Juana, one of the contestants, has created the probability distribution of her scores, shown below.
Juana’s Distribution
Score
16
17
18
19
Probability
0.10
0.30
0.40
0.20

Carroll, another player, has also practiced multiple times and created the probability distribution shown below.
                                                                                                   Carroll’s Distribution
Score
17
18
19
Probability
0.45
0.40
0.15

1. Find the expected score for each player. Write your answer in a complete sentence, in context.

2. Suppose Juana scores 16 and Carroll scores 17. The difference (J – C) of their scores is -1. Find all combinations of possible scores for Juana and Carroll that will produce a difference (J – C) of -1, and calculate the probability of each combination.

3. Calculate the probability that the difference (J – C) between their scores is -1.

4. The following table lists all possible differences in scores between Juana and Carroll and the associated probabilities.
Distribution (Juana minus Carroll)
Difference
-3
-2
-1
0
1
2
Probability
0.015


0.325
0.260
0.090


5. Complete the table and calculate the probability that Carroll’s score will be greater than Juana’s score. 

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