The answers to each of these questions are posted below--be sure to check your answers to these!!!
On Monday in class we'll move on to calculating some probabilities "without replacement" and we'll explore the conditional probability formula! See you there!
You don't know how to do all of it yet, but if you'd like to get a head start you can do some of these--here's Monday night's homework:
Monday HW:
Page 362- : 1, 3, 5, 19, 21ab, 23
And lastly, one of our classmates lost a necklace that's very important to them--if you see this necklace anywhere (including on a person) please let me know!
Here are the answers to the weekend homework so you can check (let me know if you think I made a mistake...)
Probability and Venn Diagrams:
1a) 0.76
1b) 0.14
1c) 0.24
2a) 0.14
2b) 0.23
2c) 0.77
3a) .06
3b) 0.50
3c) 0.94
4a) 0.68
4b) 0.04
4c) 0.51
A tire manufacturer designed a new tread pattern....
a. 70th percentile of stopping distances = 128.41 ft
b. P(stopping distance between 110 and 140) = 0.979
c. P(stopping distance >130) = 0.2209
d. P(at least 1 out of 5 cars stops in a distance >130) = 0.71294
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