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Thursday, December 5, 2019

Thursday HW

This has been a crazy/disjointed week with the return from break (those days are always sluggish) and a surprise snow day...this means where a little behind where we want to be pacing wise, so come ready to work tomorrow and next week. Next Monday we really have to get back into the groove/routine; we've got 10.5 days of work before our next break, and we need to make the most of them. I know it's hard to stay motivated this time of year--it is for me too--but let's keep pushing each other and keep each other on top of our game.

You have two responsibilities to take care of tonight....

1.) Play with your laptop! Hopefully you're using it to check the blog right now! 
  • Note: you won't need it in my class, so I guess it's up to you if you bring it to school. Check with your other AP teachers to see if you'll need it for them. 

2.) Do the extra credit homework! More practice = better preparation (and extra credit!)

  • p. 363-366: 12, 24, 29, 33, 45
    • 12 and 24 are similar to 11, 21, 23a shown a few blog posts below!
    • For 29 try to use the independence formula....
      • Does P(high BP) = P(high bp / high chol.)? That is, if we know someone has high cholesterol does it make them more/less likely to have high bp? 
      • Or....
        • Does P(high chol.) = P(high chol / high bp)? That is, if we know someone has high bp does it make them more/less likely to have high cholesterol?
    • 33 = more independence formula
    • Also, use the answers in the back of the book to help develop/strengthen your understanding for 29, 33
    • Always check your answers/grade yourself for full credit! Here are 12, 24:
      • 12a.) 0.62
      • 12b.) 0.867
      • 12c.) 0.194
      • 12d.) 0.66
      • *Note: b and c are conditional! And for d remember to pay attention to any overlap!
      • 24a.) P(Canada given Mexico) = 0.444
      • 24b.) No, going to Mexico and Canada are not disjoint; 4% of people have been to both.
      • 24c.) P(Canada) = 0.19, and P(Canada/Mexico) = 0.444--Therefore, someone who has traveled to Mexico is more likely to go to Canada than a random person, so going to Canada/Mexico are not independent. 

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