TEST TOMORROW!

We have our chapter 14-16 probability test tomorrow!

The best way to study is to do practice problems--you have a lot of those to choose from! 

1.) Work on the (17) probability review multiple choice questions provided in class on Friday (or below)!

• Don't worry too much about #10, there isn't anything like that on our test.
• The probability MC reviews many of the concepts we'll see on on our test!
• Check your answers!
• MC Review Answer Key:
1. D
2. D
3. A
4. A
5. D
6. A
7. C
8. B
9. C
10. D
11. E
12. B
13. A
14. D
15. A
16. E
17. D

2.) It would also be a good idea to try #37 and 38 on page 384 to make sure your comfortable with the combining random variables/Normal model stuff we worked with last week! These questions are also on the back of the #33 example we did in class Friday!

•  Answers:
• 37a) Mean = 200.57 seconds, Standard Deviation = 0.4619 seconds
• 37b) Probability of team beating its time = 0.00901
• "This team is not likely to swim faster than this time (199.48 seconds) because the probability of doing so is low (less than 1%)."
• 38a) Mean = 37.6 min, Standard Deviation = 3.6797 min
• 38b) I do not think the bike will be ready and set up as promised; the probability the bike is ready and set up in at most a half hour is only 0.01944.

3.) Another great way to study is to look over your previous quizzes!

• Look over your (two) chapter 14 quizzes (one take home, one in class) and your chapter 15 quiz!

4.) If you want some more practice/review to study for the test, check out the following in your textbook (and check your answers in the back of the book!)

• Page 384 (chapter 16): 37
• Page 402-407 (Review of Part IV = Probability Review):
• 3abc, 5, 7ab, 9a, 13b, 21, 31, 35, 37, 41

5.) Finish the "Combining Random Variables" AP multiple choice that we started today in class! 

• Here are the answers:
• 1.) D
• 2.) 0.12043 (your answer may be slightly different depending on how you rounded)
• 3.) C
• 4.) B
• 5.) B
• 6.) E
• 7.) C
• 8.) D
• 9.) D

6.) Try the "Juana and Carroll" free response question provided in class!

• Here are the answers:
• a.) Both expected values = 17.7
• If Juana and Carroll repeatedly play this game both are expected to score an average of 17.7 points per game, based on these probability models.
• b.) P(J16 and C17) = 0.045, P(J17 and C18) = 0.12, P(J18 and C19) = 0.06
• c.) 0.225
• d.) P(J-C = -2) = 0.085 (remember, probabilities must sum to 1)
• e.) 0.325
• Remember, this model is for the difference, "J-C." If Carroll is going to have a greater score than Juana, think about what type of difference 

7.) Complete the 2012 Free Response (on the back of Juana and Carroll)

• Here are the answers:
• a.) (Probabilities in order from left to right): 6/10, 3/10, 1/10 (or .6, .3, .1)
• b.) E(x) = $0.70 (*Remember to show work for this type of question)
• c.) 715 plays
• d.) 0.984435

Here are the probability review MC in case you lost yours or were absent: